Question

a hemisphere bowl is made of bress, 0.25 thickness the inner radius of the bowl is 5cm.find the ratio of outher surface area to inner surface area

Answer 1

Outer radius = Inner + Thick = (5 cm) + (0.25 cm) = 5.25 cm  

Surface area of a sphere = 4*pi*r^2  

Sa = 4 * (3.14159) * (5.25 cm)^2  

Sa = (12.57) * (27.56 cm^2)  

Sa = 346.3 cm^2

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