Question

a hemisphere bowl is made of steel 0.25 cm thick the inner radius of the bowl is 5 cm. find the outer curved surface of the bowl​

Answer 1

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Answer 2

Step-by-step explanation:

outer curved surface area = 2πr²

outer radius = inner radius + thickness

=> outer radius r = 5.25 cm

Therefore outer CSA = 2×22/7×5.25×5.25

=> 173.25 cm²