a hemisphere can bowl its made up of steel of 0.25 centimeters thickness the inner radius of bowl is 5 cm the vvolume of steel is used
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r = 5cm
thickness = 0.25cm
2/3 π r³
2/3 × 22/7 × 5³
2.09 x 125
volume = 261.25
thickness = 0.25cm
2/3 π r³
2/3 × 22/7 × 5³
2.09 x 125
volume = 261.25
aishu01:
plz mark as the brainliest
sry
find the outer csa
0.25+5
=5.25
outer csa = 2pi r square
2*22/7*5.25*5.25
173.25 cm square
2/3 * 22/7 * (173.5)^3
10895649.1875
=5.25
outer csa = 2pi r square
2*22/7*5.25*5.25
173.25 cm square
2/3 * 22/7 * (173.5)^3
10895649.1875
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