Question

a hemisphere lead of radius 8 cm is cast into a right circular cone of base radius 6 CM determine height of cone correct to 2 decimal places

Answer 1

Hey Mate

your answer is here

volume of hemisphere = volume of cone

2/3×pi×r^3 = 1/3×pi×r^2×h

h = 2×8×8×8/6×6

h = 28.44 cm

Answer 2

Given :

A hemisphere lead of radius 8 cm is cast into a right circular cone of base radius 6 CM

To Find :

Determine height of cone correct to 2 decimal places

Solution:

Radius of hemisphere = 8 cm

Volume of hemisphere =$\frac{2}{3} \pi r^3 = \frac{2}{3} \pi 8^3$

Radius of cone = 6 cm

Volume of cone = $\frac{1}{3} \pi r^2 h = \frac{1}{3} \pi (6)^2 h$

we are given that a hemisphere lead of radius 8 cm is cast into a right circular cone of base radius 6 CM

So, Volume of hemisphere = Volume of cone

$\frac{2}{3} \pi 8^3=\frac{1}{3} \pi (6)^2 h\\2 \times 8^3=(6)^2 h\\\frac{2 \times 8^3}{(6)^2}=h$

28.44=h

Hence The height of cone is 28.44 cm