A hemisphere of maximum possible diameter is placed over a cuboidal block of side 7 cm.find surface area of solid so formed
Answers
Surface area of solid= Surface area of Cuboid having side 7 cm + Surface area of Hemisphere having maximum diameter
= 6×(Side)² + 3 πR² where R is radius of sphere.
= 6×7² + 3×22/7×(7/2)²
= 6×49+ 3×22/7×49/4
=294 +115.50
= 409.50 cm²
If you will take diameter of hemisphere along the Diagonal of a cuboid it will just come out of surface i.e it will cross the boundary of cuboid.
Answer:
A hemisphere of maximum possible diameter placed over a Cuboidal block of side =7cm
Then, Radius = 7/2 CM = 3.5cm.
Now, Surface area of Cuboidal block= Total surface area of cube - Area of lower part of hemisphere + curved surface area of hemisphere.
=> 6a^2 - πr^2 + 2πr^2
=> 6×(7)^2 - 22/7×7/2×7/2 + 2×22/7×7/2×7/2
=>294 - 77/2 + 77
=> 294 - 77+154/2
=> 294 + 77/2
=> 588+77/2
=> 665/2 = 332.5cm^2.
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