a hemisphere of maximum possible diameter is placed over a cuboidal block of side 7 cm find the surface area of the solid so formed
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Surface area of solid= Surface area of Cuboid having side 7 cm + Surface area of Hemisphere having maximum diameter
= 6×(Side)² + 3 πR² where R is radius of sphere.
= 6×7² + 3×22/7×(7/2)²
= 6×49+ 3×22/7×49/4
=294 +115.50
= 409.50 cm²
If you will take diameter of hemisphere along the Diagonal of a cuboid it will just come out of surface i.e it will cross the boundary of cuboid.
HOPE IT HELPS YOU!!
= 6×(Side)² + 3 πR² where R is radius of sphere.
= 6×7² + 3×22/7×(7/2)²
= 6×49+ 3×22/7×49/4
=294 +115.50
= 409.50 cm²
If you will take diameter of hemisphere along the Diagonal of a cuboid it will just come out of surface i.e it will cross the boundary of cuboid.
HOPE IT HELPS YOU!!
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