Question

a hemisphere of radius 60 cm is surmounted by a cone of height 120 cm and the radius is 60 CM the solid already is immersed in a cylinder containing water such that it touches the bottom of the cylinder as shown if the radius of cylinder is 60 cm and height is 180 cm find the volume of the remaining water​

Answer 1

Answer:To find the volume of remaining water, first find the volume of hemispherical part then find volume of conical part of solid and then add these values to get volume of solid. Then find volume of cylinder and subract the volume of solid from it.

Step-by-step explanation:

Answer 2

Therefore the volume of the remaining water is  =360000π cm³

Step-by-step explanation:

Given , a hemisphere of radius 60 cm is surmounted by a cone of height 120 cm and the radius is 60 cm .

The volume of the cone is $=\frac{1}{3} \pi r^2 h$

                                           $=\frac{1}{3} \pi 60^2 \times 120$    cm³

                                           =144000π cm³

The volume of the sphere is $=\frac{2}{3} \pi r^3$

                                               $=\frac{2}{3} \pi \times 60^3$ cm³

                                               = 144000π cm³

Therefore the total volume of the solid is =(144000π+144000π ) cm³

                                                                     =288000π  cm³

Again, given that the radius of the cylinder is 60 cm and height is 180 cm

The volume of the cylinder $=\pi r^2 h$

                                             $=\pi \times 60^2\times 180$ cm³

                                            =648000π cm³

Therefore the volume of the remaining water is =(648000π-288000π) cm³   =360000π cm³