A hemispheric bowl made of brass has inner diameter 10.5 cm. Find the cost of tin- plating it on the inside at the rate of rupees 32 per 100 cm square
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Area of hemisphere = 2 pie r^2
= 2 ( 3.14)( 10.5/2)^2
= 173.09 cm^2
cost of plating is 32 per 100 cm^2
for 1 cm^2 cost of plating is 32/100
For 173.09 cm^2 cost of plating is 32× 173.09/100
= 55.388 rs
= 2 ( 3.14)( 10.5/2)^2
= 173.09 cm^2
cost of plating is 32 per 100 cm^2
for 1 cm^2 cost of plating is 32/100
For 173.09 cm^2 cost of plating is 32× 173.09/100
= 55.388 rs
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