A hemispheric bowl made of brass has inner diameter 10.5 cm. Find the cost of tin- plating it on the inside at the rate of rupees 32 per 100 cm square
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Hello mate!!!
Radius of hemisphere = r = /2 = (10.5/2) cm = 5.25 cm
Curved surface area of the hemisphere = 22 = (2×22/7×5.25×5.25) cm2 = 173.25 cm2
Cost of tin-plating 100 cm2 = Rs 16
Cost of tin-plating 1 cm2 = Rs 1/100 × 16
Cost of tin-plating 173.25 cm2 = Rs 1/100 × 16 × 173.25 = Rs 27.72
∴ Cost of tin-plating the hemisphere is Rs 27.72
Hope it helps you
Radius of hemisphere = r = /2 = (10.5/2) cm = 5.25 cm
Curved surface area of the hemisphere = 22 = (2×22/7×5.25×5.25) cm2 = 173.25 cm2
Cost of tin-plating 100 cm2 = Rs 16
Cost of tin-plating 1 cm2 = Rs 1/100 × 16
Cost of tin-plating 173.25 cm2 = Rs 1/100 × 16 × 173.25 = Rs 27.72
∴ Cost of tin-plating the hemisphere is Rs 27.72
Hope it helps you
sanjaysensharma123:
Rs 16 no Rs 32 in my question
Your ans is wrong
keep quiet she is
randi
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