A Hemispherical ball is made up of Steel 0.25 CM thick the inner radius of the bowl is 5 cm find the outer curved surface area of the bowl.
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Answer:
Outer radius = inner radius + thickness 0.25cm + 5cm = 5.25cm c.s.a = 2pie rsquare 2× 22/7 × 5.25 × 5.25= 346.5 cm square
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SOLUTION:-
Given:-
- Thickness of the Steel = 0.25cm
- Inner radius of the bowl = 5cm.
Need to find:-
- Outer curved surface area of the bowl.
Step by step explanation-
As it given that,
Radius of the bowl = 5cm.
Hence,
Outer curved surface area = 2πr²
=> 2×22/7×5.25×5.25
=> 173.25cm²
Hence, outer curved surface area of the bowl is 173.25cm².
ADDITIONAL INFORMATION:-
Curved surface area of sphere = 2πr²
Total surface area of sphere = 4πr²
Surface area of hemisphere = 3πr²
Volume of the sphere = 4/3πr³
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