Question

A Hemispherical ball is made up of Steel 0.25 CM thick the inner radius of the bowl is 5 cm find the outer curved surface area of the bowl.
​

Answer 1

Answer:

Outer radius = inner radius + thickness 0.25cm + 5cm = 5.25cm c.s.a = 2pie rsquare 2× 22/7 × 5.25 × 5.25= 346.5 cm square

HOPE IT WOULD HELP YOU AND MAKE ME BRAINIEST...

Answer 2

SOLUTION:-

Given:-

• Thickness of the Steel = 0.25cm
• Inner radius of the bowl = 5cm.

Need to find:-

• Outer curved surface area of the bowl.

Step by step explanation-

As it given that,

Radius of the bowl = 5cm.

Hence,

Outer curved surface area = 2πr²

=> 2×22/7×5.25×5.25

=> 173.25cm²

Hence, outer curved surface area of the bowl is 173.25cm².

ADDITIONAL INFORMATION:-

Curved surface area of sphere = 2πr²

Total surface area of sphere = 4πr²

Surface area of hemisphere = 3πr²

Volume of the sphere = 4/3πr³