A hemispherical bowl an inner diameter of 14cm Find the cost of tin-plating it on the inner side at the rate of Rs.20per
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Step-by-step explanation:
inner diameter =14 cm
inner radius =14/2 =7cm
curved surface area=2πr^2
=2×22/7×7×7
=308 cm^2
cost of tin plating per 1 cm^2= 20 ruppes
cost of tin plating per 308 cm^2=308 ×20
=6160 cm^2
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