Question

A hemispherical bowl has a radius 3.5 cm. What would be the volume of water it would contain?

Answer 1

hope it helped u .....the volume of water in the container is equal to the volume the container

Answer 2

The volume of water is 89.83 cc, that the hemispherical bowl would contain.

Given:

• A hemispherical bowl of radius 3.5 cm.

To find:

• Find the volume of water it would contain.

Solution:

Formula/ Concept to be used:

• Volume of hemisphere:$\bf V = \frac{2}{3} \pi {r}^{3}$here, r: radius of hemisphere.

Step 1:

Write the given dimension.

It has been clear that;

radius (r)= 3.5 cm

Step 2:

Find the volume of hemisphere.

$V = \frac{2}{ 3} \times \frac{22}{7} \times ( {3.5)}^{3} \: {cm}^{3}$

or

$V = \frac{2}{ 3} \times \frac{22}{ \cancel7} \times \frac{ \cancel{35} \: 5}{10 } \times\ \frac{35}{10 }\times \frac{35}{10 }\: {cm}^{3}$

or

$V= \frac{2}{3} \times 22 \times \frac{5}{10} \times \frac{35}{10} \times \frac{35}{10}$

or

$V = \frac{1}{3} \times 11 \: \cancel{22} \times \frac{\cancel{35} \: 7}{ \cancel{10} \: \cancel5} \times \frac{35}{10}$

or

$V= \frac{11 \times 7 \times 35}{30}$

or

$V= \frac{2965}{30}$

or

$\bf \red{V = 89.83 \: {cm}^{3}}$

Thus,

The volume of water is 89.83 cc, that the hemispherical bowl would contain.

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