A hemispherical bowl has a radius of 3.5 CM. What would be the volume of water it would contain
Answers
Answered by
1
Answer:
89.83
Step-by-step explanation:
=2/3×22/7×3.5³
=2/3×22×.5×3.5×3.5
=2×134.75/3
=269.5/3
=89.83
Answered by
1
Step-by-step explanation:
=2/3×22/7×3.5
=2/3×22×.5×3.5×3.5
=2×134.75/3
=269.5/3
=89.83
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