Question

a hemispherical bowl has inner diameter 11.2 cm find the volume of milk it can hold​

Answer 1

Answer:

• Volume of cone = 367.95 cm³

Step-by-step explanation:

Refers to the attachment!!!

Answer 2

$\bf{\Huge{\boxed{\tt{\purple{ANSWER\::}}}}}$

$\bf{\Large{\underline{\bf{[Given\::]}}}}}$

A hemispherical bowl has inner diameter 11.2cm.

$\bf{\Large{\underline{\bf{[To\:find\::]}}}}$

The volume of milk it can hold.

$\bf{\Large{\underline{\tt{\green{Explanation\::}}}}}$

We know that volume of hemisphere:

$\bf{\Large{\boxed{\tt{Volume\:=\:\frac{2}{3} \pi r^{3} }}}}$

$\bf{We\:have}\begin{cases}\sf{Inner\:diameter\:(d)=\:11.2cm}\\ \\\sf{Radius\:(r)\:=\frac{11.2}{2} cm}\end{cases}}$

Therefore,

$\longmapsto\sf{Volume\:=\:\frac{2}{3} *\frac{22}{7} *(\frac{11.2}{2})^{3} }$

$\longmapsto\sf{Volume\:=\:\frac{2}{3} *\frac{22}{7} *\frac{11.2}{2}*\frac{11.2}{2}*\frac{11.2}{2}}$

$\longmapsto\sf{Volume\:=\:\frac{\cancel{2}}{3} *\frac{\cancel{22}}{\cancel{7}} *\frac{\cancel{11.2}}{\cancel{2}}*\frac{11.2}{\cancel{2}}*\frac{11.2}{2}}$

$\longmapsto\sf{Volume\:=\:\frac{11*1.6*11.2*11.2}{6}\:cm^{3} }$

$\longmapsto\sf{Volume\:=\:\frac{11*16*112*112}{6*1000} \:cm^{3} }$

$\longmapsto\sf{Volume\:=\:\cancel{\frac{2207744}{6000}} \:cm^{3} }$

$\longmapsto\sf{\red{Volume\:=\:367.95\:cm^{3} }}$

Thus,

$\bf{\Large{\boxed{\rm{The\:volume\:of\:milk\:it\:can\:hold\:\:\implies367.95cm^{3} }}}}}$