Question

A hemispherical bowl has radius of 3.5 cm. what would be the volume of water it would contain.

Answer 1

Answer:

Volume of water = Volume of Hemispherical bowl

= 2/3πr³

= 2/3*22/7*(3.5)³

= 22*12.25/3

= 89.8cm³ is the answer

Answer 2

Step-by-step explanation:

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