Question

a hemispherical bowl is made 0.25 cm thickness. the inner radius of the bowl is 5cm. find the ratio of outer surface area to inner surface area.​

Answer 1

Step-by-step explanation:

Inner Radius = r =5cm

Outer Radius =R = 5+0.25 = 5.25 cm

Ratio of outer surface area to inner surface area

= 2πR^2/2πr^2

= R^2/r^2

= (5.25/5)^2

= 27.5625/25

= 275625/250000

= 441/400

= 441 : 400

thanks u

Answer 2

Answer:

441:400 is the right answer