A hemispherical bowl is made of brass, 0.25 cm. thickness. The inner radius of the bowl
is 5 cm. Find the ratio of outer surface area to inner surface area.
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Answer:
inner radius r, = 5 cm
thickness of bowl = 0.25 cm
Step-by-step explanation:
solu=. outer radius r =( inner radius + thickness )
outer radius = ( 5+0.25)=5.25
radio of their s.a= 2πr,\2πr
=2×22×5.25×5.25×7/2×22×7×5×5
=1.5×1.5
=2.25
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