A hemispherical bowl is made of brass, 0.25cm. thickness. The inner radius of the bowl is 5 cm. Find the ratio of outer surface area to inner surface area.
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Inner radius = 5 cm
Thickness = 0.25 cm
Outer radius = Inner + Thick = (5 cm) + (0.25 cm) = 5.25 cm
Surface area of a sphere = 4*pi*r^2
Sa = 4 * (3.14159) * (5.25 cm)^2
Sa = (12.57) * (27.56 cm^2)
Sa = 346.3 cm^2
Since it's a hemisphere = 0.5 * Sa = (0.5) * (346.3 cm^3) = 173.2 sq cm
devansh7972:
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