Question

A hemispherical bowl is made of brass, 0.25cm. thickness. The inner radius of the bowl is 5 cm. Find the ratio of outer surface area to inner surface area.

Answer 1

Inner radius = 5 cm  

Thickness = 0.25 cm  

Outer radius = Inner + Thick = (5 cm) + (0.25 cm) = 5.25 cm  

Surface area of a sphere = 4*pi*r^2  

Sa = 4 * (3.14159) * (5.25 cm)^2  

Sa = (12.57) * (27.56 cm^2)  

Sa = 346.3 cm^2  

Since it's a hemisphere = 0.5 * Sa = (0.5) * (346.3 cm^3) = 173.2 sq cm

Answer 2

Answer:

Step-by-step explanation: