a hemispherical bowl is made of brass has inner diameter of 5cm and thickness is o.25cm. Find the cost of tin plating all over it at the rate of rs 16 per 100cm^2
[It is not the same question of NCERT]
Answers
Answer:
Rs. 13.21
Step-by-step explanation:
inner radius = 5/2
area of plating inner surface = 2Πr² = 2×(22/7)×(5/2)² = 39.26 cm²
outer radius = 5.25/2
area of plating outer surface = 2Πr² = 2×(22/7)×(5.25/2)² = 43.31 cm²
Total area of plating = 39.26+43.31 = 82.57cm²
cost of plating 100cm² = Rs. 16
cost of plating 1cm² = 16/100 = Rs. 0.16
cost of plating 82.57cm² = 82.57× 0.16 = Rs. 13.21
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Rs. 13.21
Step-by-step explanation:
inner radius = 5/2
area of plating inner surface = 2Πr² = 2×(22/7)×(5/2)² = 39.26 cm²
outer radius = 5.25/2
area of plating outer surface = 2Πr² = 2×(22/7)×(5.25/2)² = 43.31 cm²
Total area of plating = 39.26+43.31 = 82.57cm²
cost of plating 100cm² = Rs. 16
cost of plating 1cm² = 16/100 = Rs. 0.16
cost of plating 82.57cm² = 82.57× 0.16 = Rs. 13.21
#Hopeithelps
Rs. 13.21
Step-by-step explanation:
inner radius = 5/2
area of plating inner surface = 2Πr² = 2×(22/7)×(5/2)² = 39.26 cm²
outer radius = 5.25/2
area of plating outer surface = 2Πr² = 2×(22/7)×(5.25/2)² = 43.31 cm²
Total area of plating = 39.26+43.31 = 82.57cm²
cost of plating 100cm² = Rs. 16
cost of plating 1cm² = 16/100 = Rs. 0.16
cost of plating 82.57cm² = 82.57× 0.16 = Rs. 13.21
#Hopeithelps
Rs. 13.21
Step-by-step explanation:
inner radius = 5/2
area of plating inner surface = 2Πr² = 2×(22/7)×(5/2)² = 39.26 cm²
outer radius = 5.25/2
area of plating outer surface = 2Πr² = 2×(22/7)×(5.25/2)² = 43.31 cm²
Total area of plating = 39.26+43.31 = 82.57cm²
cost of plating 100cm² = Rs. 16
cost of plating 1cm² = 16/100 = Rs. 0.16
cost of plating 82.57cm² = 82.57× 0.16 = Rs. 13.21
#Hopeithelps