a
hemispherical bowl is made of steel, 0.25 cm thick. The inner radius of the bowl is
5 cm. Find the outer curved surface area of the bowl.
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18
Answer:
r=5cm, thickness of steel sheet =0.25cm
⇒ R=5cm+0.25cm=5.25cm
outer curved surface area of the bowl =2πR²
=2×22/7×525/100×525/100
=173.25cm²
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