Question

a hemispherical bowl is made of steel 0.25 cm thick. The inner radius of the bowl is 5cm find the outer CSA of the bowl

Answer 1

Step-by-step explanation:

Radius=5cm

Thickness=0.25cm

Total radius=5.25cm

CSA of a hemisphere = 2pie r^2

=2×22/7×5.25^2

=663/4

=165.75 cm^2

Answer 2

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$\small\bold{Inner \: radius \: of \: the \: bowl \: = }$ 5cm

$\small\bold{Thickness \: of \: the \: steel \: =}$ 0.25cm

$\small\bold{Outer \: radius \: of \: the \: bowl \: =}$ 5+0.25=5.25cm

$\small\bold{Outer \: Curved \: surface \: of \: the \: hemispherical \: bowl \: =}$ 2πr²

= 2× $\large\dfrac{22}{7}$ × (5.25)² = 172.25 cm²

${\huge{\red{\underline{\overline{\mathscr{\red{Hope \: This \: Helps \: You}}}}}}}$