A hemispherical bowl is made of steel, 0.25 cm thick. The inner radius of the bowl is 5 cm, find the outer curved surface area of the bowl. (Take pie=3.14)
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thickness of hemispherical bowl =0.25 cm
inner radius of hemispherical bowl=5 cm
outer radius of hemispherical bowl = (5+0.25) cm
=5.25 cm
outer curved surface area of the bowl=2
=6.18*5.25*5.25
=6.18*27.5
=170.33
inner radius of hemispherical bowl=5 cm
outer radius of hemispherical bowl = (5+0.25) cm
=5.25 cm
outer curved surface area of the bowl=2
=6.18*5.25*5.25
=6.18*27.5
=170.33
adarshkumar610:
its answer will be 173.0925
ja jara calculator se kar le or mene haat se keya hai same hoge
mera calculation tujhse lakh guna tej hai mai vedic maths ka champ hu
tera answer toh galat hai
kyon ki 3.14×2=6.28 hota hain 6.18 nahin. aur apne app ko calculator samaghta hain hamse takkar le kar dekho
bhai bhai mene jalte type kardeya copy me mene ab wapas deka
sorry
2ke jage 1 lekdeya
i am not able to edit
no problem
Answered by
1
inner radius =5cm
thickness=0.25cm
so,outer radius=5+0.25
=5.25cm
outer c.s.a=2×pi×r^2
=2×3.14×5.25^2
=6.28×441/16
=173.0925cm^2
thickness=0.25cm
so,outer radius=5+0.25
=5.25cm
outer c.s.a=2×pi×r^2
=2×3.14×5.25^2
=6.28×441/16
=173.0925cm^2
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