Question

a hemispherical bowl is made of steel 0.25 cm thick the inner radius of the bowl is 5 cm find the outer curved surface area of bowl
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Answer 1

Answer :-

we need to find out outer curved surface area

hence , we need to find out Outer radius

Given inner radius = 5 cm

hence Outer radius = r = 5 + 0.25 cm = 5.25 cm

$Hence, outer \: curved \: \\ surface = 2 \pi {r}^{2}$

$(2 \times \frac{22}{7} \times 5.25 \times 5.25) {cm}^{2}$

$= \geqslant 173.25 \: {cm}^{2}$

Answer 2

Question:-

A hemispherical bowl is made of steel 0.25 cm thick the inner radius of the bowl is 5 cm.

To Find :-

find the outer curved surface area of bowl.

Sollution :-

Here,

inner radius= 5cm.

thickness of steel sheet =0.25cm.

now adding both, we get!

Radius of bowl(r)= 5+0.25⇒5.25cm.

Outer curved surface of the bowl = $\boxed{2\pi {r}^{2}}$

⇒$2 \times \frac{22}{7} \times {5.25}^{2}$

⇒$2 \times \frac{22}{7} \times 27.56$

⇒${173.25 \: cm^{2}}$