Question

A hemispherical bowl is made of steel, 0.25 cm thick. The inner radius of the bowl is 5 cm. Find the outer curved surface area of the bowl.

Answer 1

Given:-

• Inner radius of the bowl = 5cm
• Thickness of the bowl = 0.25cm
• External radius = 5 + 0.25 = 5.25cm

step-by-step explaination:-

• We know that Outer curved surface area of the bowl = 2πr²

• By substituting the values,

Outer curved surface area of the bowl =

• ⇒ 2 × (22/7) × (5.25)²

• ⇒2 × (22/7) × 27.5625

• ⇒173.25cm²

So we get Outer curved surface area of the bowl = 173.25 cm²

Therefore, the outer curved surface area of the bowl is 173.25 cm².

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