Question

A hemispherical bowl is made of steel 0.25 CM thick the inner radius of the ball is 5 cm find the outer surface area of the bowl

Answer 1

Answer:

Step-by-step explanation:

Outer radius =5.25

Outer sa=2*pi*r^2=2*22/7*5.25*5.25

=173.25cm^2

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Answer 2

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$\small\bold{Inner \: radius \: of \: the \: bowl \: = }$ 5cm

$\small\bold{Thickness \: of \: the \: steel \: =}$ 0.25cm

$\small\bold{Outer \: radius \: of \: the \: bowl \: =}$ 5+0.25=5.25cm

$\small\bold{Outer \: Curved \: surface \: of \: the \: hemispherical \: bowl \: =}$ 2πr²

= 2× $\large\dfrac{22}{7}$ × (5.25)² = 172.25 cm²

${\huge{\red{\underline{\overline{\mathscr{\red{Hope \: This \: Helps \: You}}}}}}}$