A hemispherical bowl is made of steel 0.25 cm thick the inner radius of the ball is 4 cm find the volume of steel used in making the bowl.
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Answer:
41.28 cm³
Step-by-step explanation:
we have
r=inner radius of the bowl=5 cm
R= outer radius of the bowl = 5.25 cm
therefore volume of the steel
= 2/3π[ R³-r³]
=2/3*22/7*{[5.25]³-5³} cm³
=41.28 cm³
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