Question

A hemispherical bowl is made of steel 0.25cm thick.the inner radius of the bowl is 4cm. find the volume of steel used

Answer 1

Hope this will help.

Answer 2

Answer:

$26.72 cm^3$  

Step-by-step explanation:

Inner radius = 4 cm

Formula of volume of hemisphere = $\frac{2}{3} \pi r^{3}$

So, volume of inner hemisphere =  $\frac{2}{3} \times 3.14 \times 4^{3}$

                                                 =  $133.97 cm^3$  

Now A hemispherical bowl is made of steel 0.25cm thick

So, the outer radius = 4+0.25=4.25 cm

So, volume of outer hemisphere =  $\frac{2}{3} \times 3.14 \times 4.25^{3}$

                                                      =  $160.69 cm^3$  

Thus the volume of steel used = Outer volume - Inner volume

                                                     =  $160.69 -133.97$  

                                                      =  $26.72 cm^3$  

Hence  the volume of steel used is  $26.72 cm^3$