A hemispherical bowl is made of steel 0.5cm thick. The inside radius of the bowl is 4cm. Find the volume of steel used in making the bowl.
Answers
≡QUESTION≡
A hemispherical bowl is made of steel 0.5 cm thick. The inner radius of the bowl is 4 cm. Find the volume of steel used in making the bowl.
║⊕ANSWER⊕║
Given
Thickness = 0.5 cm
Inner radius = 4 cm
So,
The volume of the inner hollow space is = (2/3)π(4)³
= (2/3)×(22/7)× 64
= 134.09 cm³
The radius with included metal is = (4+0.5)
= 4.5 cm
The volume with included metal = (2/3)π(4.5)³
= (2/3)×(22/7)×(91.125)
= 190.92 cm³
So,the volume of the metal = (190.92-134.09) cm³
= 56.83 cm³ (approx.)