Question

A hemispherical bowl is made of steel 0.7cm thick.The inner radius is 7cm.find the volume of the steel used to make the bowl.

Answer 1

Answer:

The volume of steel used to make the hemispherical bowl is 237.66032 cm³

Step-by-step explanation:

We know that,

Volume of a hollow sphere= (4/3)π (R³ - r³)

Volume of hollow hemisphere= (2/3)π(R³ - r³)

Thus, according to the problem,

Volume of the bowl= (2/3)π [(4.5)³-(4)³]

Now, on using identity

a³ - b³ = (a-b) × (a²+ab+b²)

=>(2/3)π [(7.7-0.7){(7.7)²+(7.7)×(7)+(7)²}]

=>(2/3)π [(0.7)(59.29 +53.9+49)]

=>(2/3)π [(0.7) × (162.19)]

=>2π (37.844)

=>(2) × (3.14) × (37.844)

=>237.66032 cm³

Hence,

The volume of steel used to make the hemispherical bowl is 237.66032 cm³