Question

A hemispherical bowl is made of steel, 1 cm thick. The inner radius of the bowl is 4 cm. find the outer curved surface area of the bowl ​

Answer 1

Answer :-

• CSA of Bowl = 157.14 cm² [Approx.]

Given :-

• Thickness of Bowl = 1 cm
• Inner Radius of Bowl = 4 cm

To Find :-

• CSA of Bowl = ?

Explanation :-

In order to find the Outer CSA of the Bowl, First we need to find the Outer Radius of the Bowl.

$\blue { \boxed { \bf \bigstar \: Outer \: Radius = Thickness + Inner \: Radius \: \bigstar }}$

$\rm \hookrightarrow Outer \: Radius = (1 + 4) \: cm = \bold{5 \: cm}$

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As we Know,

$\green { \boxed { \bf \bigstar \: CSA \: of \: Hemisphere = 2 \pi r^2 \: \bigstar }}$

$\rm \hookrightarrow \: 2 \pi r^2 = Outer \: CSA \: of \: Bowl$

$\rm \hookrightarrow \: 2 \times \dfrac{22}{7} \times (5)^2$

$\rm \hookrightarrow \: 2 \times \dfrac{22}{7} \times 5 \times 5$

$\rm \hookrightarrow \: \dfrac{44}{7} \times 25$

$\rm \hookrightarrow \: \dfrac{1100}{7}$

$\red { \underline { \boxed { \bf \hookrightarrow \: 157.14 \: cm^2 }}} \qquad \bold{[Approx.]}$

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Hence, the Outer CSA of the Hemispherical Bowl is 157.14 cm² [Approx.]