Question

A hemispherical bowl is made of steel, 1cm thick. The inner radius of the bowl is 6cm. The outer curved surface area of the bowl is ____
1 point
464 cm²
466 cm²
308 cm²
462 cm²​

Answer 1

Given:-

• Inner radius of Bowl = 6cm

• Thickness of Bowl = 1cm

To Find:-

• The Outer Curved Surface area of the bowl is.

Formulae used:-

• C. S. A of hemisphere = 2πr²

Where,

• r = radius of Hemisphere

Now,

→ Outer radius = Inner radius + Thickness

→ Outer radius = 6 + 1

→ Outer radius = 7cm

Therefore,

→ C. S. A of Hemisphere = 2πr²

→ C. S. A of Hemisphere = 2 × 3.14 × (7)²

→ C. S. A of Hemisphere = 2 × 3.14 × 49

→ C. S. A of Hemisphere = 307.72cm²

Hence, The CSA of bowl is 307.72cm².

Therefore, Option "c" is Correct.

Answer 2

Answer:

Given:

• Thickness of the Bowl = 6 cm

• Inner radius of the Bowl = 1 cm

To find:

• The outer curved surface area of the bowl

Formula:

• Curved Surface Area of Hemisphere = 2πr²

In short form Curved surface Area is C.S.A

Now,

$\sf\implies$ Outer radius= Inner radius + Thickness

$\sf\implies$ Outer radius= 6+1

= 7 cm

Therefore,

$\sf\implies$ C.S.A = 2πr²

$\sf\implies$ C.S.A = 2 ×3.14× (7)²

$\sf\implies$ C.S.A = 2× 3.14 × 49

$\sf\implies$ C.S.A = 308 cm²

• So,the the outer curved surface area of the bowl is 308cm²