Question

A hemispherical bowl is made of steel of 0.25 cm thickness. The inner radius of the bowl is 5 cm. The
volume of steel used is​

Answer 1

Answer:

Outer radius of hemispherical bowl = R = r + 0.25

= 5 + 0.25 = 5.25 cm

Outer curved surface area of bowl = 2πR2 = 2 x 22/7 x (5.25)2

= 2 x 22 x 5.25 x 0.75 = 173.25 cm2