Question

A hemispherical bowl is made of steel sheet 5.8 cm thick, the inside radius of the bowl is 5 cm. volume of steel used in making it is

Answer 1

Thickness = 5.8 cm

r1 = 5cm

r2 = r1 + thickness
= 5 + 5.8 = 10.8 cm

Volume of sheet
$= (2 \div 3 )\: \pi \:( r2 {}^{3} - r1 {}^{3} )$

$(2 \div 3)\pi(10.8 {}^{3} - 5 {}^{3})$

$0.66 \times 3.14(1259.71 - 125)$


$2.07 \times 1134.71$

$2348.84 \: cm {}^{3}$



Thanks