Question

A hemispherical bowl is made up of brass 0.25 CM thickness the inner radius of the bowl is 5 cm find the ratio of outer surface area to inner surface area

Answer 1

A1/A2 = 2πr²/2πR²
where r= 5+0.25 = 5.25cm
R= 5 cm
A1/A2 = r²/R²

Answer 2

Answer:

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