Question

A hemispherical bowl is made up of Steel, 0.25 CM thick. The inner radius of the ball is 5 cm. Find the outer curved surface area of the bowl ​

Answer 1

Answer:

173.25 cm²

Step-by-step explanation:

Given--->

Thickness of bowl = 0.25 cm

Inner radius of bowl = 5 cm

To find --->

Outer curved surface area of the bowl

Solution--->

Inner radius of bowl = 5 cm

Thickness of bowl = 0.25 cm

Outer radius of bowl = Inner radius of

bowl + Thickness of bowl

= 5 + 0.25

Outer radius of bowl = 5.25 cm

Outer curved surface area of hemispherical bowl= 2π r²

= 2 × 22 / 7 × ( 5.25 )²

= 2 × 22 / 7 × 5.25 × 5.25

= 2 × 22 × 0.75 × 5.25

= 173.25 cm²

Additional information--->

1) Volume of hemisphere = 2/3 π r³

2) Volume of sphere = 4/3 π r³

3) Surface area of sphere = 4 π r²

4) Total surface area of solid hemisphere = 3 π r²

5) Curved surface area of hemisphere

= 2 π r²

Answer 2

Answer:

Step-by-step explanation:

Given;      

inner radius = 5cm

we ned to find outer curve so we nneed to find outer radius.

outer radius ,r = 5+ 0.25 =  5.25

we know that the outer curved surface = 2πr²

put the values

(2×$\frac{22}{7}$×5.25 ×5.25)cm²

173.25cm²