A hemispherical bowl is made up of Steel 0.25 CM thick the inner radius of the bowl is 4 cm find the volume of Steel used in making the bowl
Answers
Answered by
2
The inner radius(r)=4 cm and outer radius is (R)0.25+4=4.25
Volume of silver used:
2/3×pi×R³-2/3×pi×r³=2/3×pi(R³-r³)
=2/3×22/7(4.25³-4³)
=44/21(76.765625-64)
=44/21(12.765625)
=561.6875/21
=26.74702381
Ans:approximately 27cm3
Volume of silver used:
2/3×pi×R³-2/3×pi×r³=2/3×pi(R³-r³)
=2/3×22/7(4.25³-4³)
=44/21(76.765625-64)
=44/21(12.765625)
=561.6875/21
=26.74702381
Ans:approximately 27cm3
Haeshu2002:
Is dat correct
ok
thx
Similar questions