Question

A hemispherical bowl is made up of steel 0.25 cm thick. the inside radius of the bowl is 5cm. find the volume of steel used in making the bowl
Plz fast answer

Answer 1

41.276(approx.)cm^3
the thickness + inner radius gives the outer radius .
so if we subtract the outer volume from inner volume we get the volume of the bowl

Answer 2

Given:-

• A hemispherical bowl is made of steel 0.25 cm thick. The inside radius of the bowl is 5 cm.

To find:-

• Find the volume of steel used in making the bowl.

Solutions:-

• Inner radius of the bowl (r) = 5cm.
• Thickness of the iron sheet = 0.25cm.

So,

The outer radius of the tank (R) = Inner radius + thickness of the sheet

=> 5 + 0.25

=> 5.25

Now,

The volume of a hemispherical shell.

Volume of a hemispherical shell => 2/3 π(R³ - r³)

=> 2/3 × 22/7 × [(5.25)² - (5)²]

=> 2 × 22 × [144.70 - 125]/21

=> 44 × 19.7 /32

=> 41.28cm³

Hence, the volume of the iron used take the tank is 41.28cm³.

Some Important:-

• The surface area of a sphere = 4πr²
• The curved surface area of hemisphere = 2πr²
• The total surface area of hemisphere = 3πr²
• The volume of the sphere = 4/3 πr²
• The volume of the hemisphere = 2/3 πr²