Question

a hemispherical bowl is made up of steel 0.25cm thick. Inner radius of bowl is 5cm. Find outer curved surface area of bowl. (answer is 173.25)

Answer 1

inner radius of hemispherical bowl = 5cm
thickness of bowl = 0.25 cm
outer radius ( R) of hemispherical bowl= ( 5+0.25)cm
= 5.25cm
2* 22/7 ( 5.25) square
173.25cm square

....

Answer 2

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$\small\bold{Inner \: radius \: of \: the \: bowl \: = }$ 5cm

$\small\bold{Thickness \: of \: the \: steel \: =}$ 0.25cm

$\small\bold{Outer \: radius \: of \: the \: bowl \: =}$ 5+0.25=5.25cm

$\small\bold{Outer \: Curved \: surface \: of \: the \: hemispherical \: bowl \: =}$ 2πr²

= 2× $\large\dfrac{22}{7}$ × (5.25)² = 172.25 cm²

${\huge{\red{\underline{\overline{\mathscr{\red{Hope \: This \: Helps \: You}}}}}}}$