Question

A hemispherical bowl is made up of stone whose thickness is 5 cm if the inner radius is 35 cm find the total surface area of the bowl​

Answer 1

$<b>let R be outer radius and 'r' inner radius</b>$

the thickness of ring = 5 cm

$<b>R = (r + 5 ) cm</b>$

R = (35 + 5) cm

R = 40 cm

$<b>TSA = CSA of outer hemisphere + CSA of inner hemisphere + area of ring</b>$

= 2πR² + 2πr² + π(R² - r²)

= π(2R² + 2r² + R² - r²)

= 22/7 (3R² + r²)

= $<b>18935.71 cm²</b>$ (approx).

Answer 2

ANSWER

18935.71$cm^2$

Step By Step Explanations

plz refer to the attachment for a detailed answer with explaination.

Remember

-Curved surface Area of hemisphere =$2\times\pi\times r^2$

-Hemisphere is just a half piece of Sphere which is equally divided to form two equal pieces of Sphere.

-Volume of hemisphere = 2/3 $\pi\times r ^3$

-Total surface area of a hemisphere

= $3\times\pi\times r^2$