Question

A hemispherical bowl mada of brass has inner diameter 10.5cm.Find the cost of tin -plating it on the inside at the rate of ₹16per 100cm​

Answer 1

Hey mate here is your answer

# Diameter of hemispherical bowl = 10.5 cm

# Radius of hemispherical bowl = 5.25 cm

# CSA of hemisphere = 2πr^2

= 2×22/7×5.25×5.25

= 44/7×27.56

= 173.23 cm^2

# Cost of tin plating for 100 cm^2= ₹16

# Cost of tin plating for 173.23 cm^2 = 173.23 × 16

= ₹ 2771.67

Hope it helps you.

Thank you.