A hemispherical bowl made of brass has inner diameter 10.5 cm. What is the cost of tin-plating it on
the inside at the rate of Rs.7 per 100 sq.cm.?
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Answer:
48.49 rupees
Step-by-step explanation:
Tin plating is over the inner surface area of bowl.
Curved surface area= 2pi r² = 2 × 10.5² × pi = 220.5 pi cm²
Cost per cm² = 7/100
Total cost of 220.5 pi cm² = 7/100 × 220.5 pi = 4849.048/100 = 48.49 rupees
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