A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of
areas of the
5.
tin-plating it on the inside at the rate of 16 per 100 cm?
Answers
Answered by
2
Answer:
27.72Rs
Step-by-step explanation:
Answer
d=10.5cm
r=
2
d
=
2
10.5
=5.25
Curved surface area of hemisphere=2πr
2
=2π(5.25)
2
=173.25cm
2
Cost of tin plating 100cm
2
=16Rs
Cost of tin plating 1cm
2
=
100
16
Rs
Cost of tin plating 173.25cm
2
=
100
16
×173.25=27.72Rs
Cost of tin plating=27.72Rs
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