A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of
tin-plating it on the inside at the rate of 16 per 100 cm².
Answers
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Answer:
D = 10.5cm
r = d = 10.5 = 5.25
2 2
Curved surface area of hemisphere =
2πr² = 2πr( 5.25 )² = 173.25cm²
cost of tin plating 100cm² = 16Rs
Cost of tin plating 1cm² = 16 Rs
100
Cost of tin plating 173.25cm² = 16 ×
100
173.25 = 27.72Rs
Cost of tin plating = 27.72Rs
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