Question

A hemispherical bowl made of brass has inner diameter 10.5cm.Find the cost of tin plating it on the side at the rate of Rs.16 per 100 square cm

Answer 1

Here we will tin-plate the inside of the hemisphere So, We need to find the curved surface area of hemisphere

 Radius of hemisphere = r = /2 = (10.5/2) cm = 5.25 cm

 Curved surface area of the hemisphere = 22 = (2×22/7×5.25×5.25) cm2 = 173.25 cm2

Cost of tin-plating 100 cm2 = Rs 16
 
Cost of tin-plating 1 cm2 = Rs 1/100 × 16
 
Cost of tin-plating 173.25 cm2 = Rs 1/100 × 16 × 173.25 = Rs 27.72
 
∴ Cost of tin-plating the hemisphere is Rs 27.72

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Answer 2

Here we will tin plate the inside of the hemisphere so we need to find the curved surface area of hemisphere

Radius of hemisphere =r=12=(10.5/2)

Cm=5.25 cm

Curved surface area of the hemisphere =22=(2*22/7*5.25*5.25)cm square

Cost of tin plating 100 cm sq =16

Cost of tin plating 1cmsq =rupee 1/100 *16

Cost of tin plating 173.25cmsq=rupee 1/100*16*173.25 =27.72

Cost of tin plating the hemisphere is rupee 27.72

Step-by-step explanation: