Question

A hemispherical bowl made of brass has inner diameter 10.5cm.what is the cost of tin plating it on the inside at the rate of 4per100square metre.​

Answer 1

Answer:

Rs. 6.93

Step-by-step explanation:

radius = 10.5/2 cm

Area of plating = 2Πr² = 2×(22/7)×(10.5/2)² = 173.25 cm²

Cost of plating 100cm² = Rs. 4

Cost of plating 1cm² = 4/100 = Rs. 0.04

Cost of plating 173.25 cm² = 173.25 × 0.04 = Rs. 6.93

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