A hemispherical bowl made of brass has inner diameter 10.5cm. Find the cost of tin - plating it on the inside at the rate of rs 16 per 100 cm2.
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Here we will tin-plate the inside of the hemisphere So, We need to find the curved surface area of hemisphere
Radius of hemisphere = r = Diameter (10.5) cm = 5.25 cm
=
2
Curved surface area of the hemisphere = 2rr²
= (2x ² x 5.25 x 5.25) cm²
= 173.25 cm²
Cost of tin-plating 100 cm² = Rs 16
Cost of tin-plating 1 cm² = Rs * 16
100 Cost of tin-plating 173.25 cm2 = Rs. x 16 x 173.25 1
100
= Rs 27.72
Cost of tin-plating the hemisphere is Rs 27.72
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Hope it's correct thank you
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