Question

A hemispherical bowl made of iron has inner radius 7cm. Find the cost of polishing inner hollow portion of bowl at the rate of ruppes 10 per 100cm^2

Answer 1

Step-by-step explanation:

curved area of hemisphere = 2πr^2

so CSA= 2×22÷7 ×49

308

the cost of polishing the inner surface of hemisphere is 308/100 (10)=30.8 rupees