A hemispherical bowl made of iron has inner radius 7cm. Find the cost of polishing inner hollow portion of bowl at the rate of ruppes 10 per 100cm^2
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Step-by-step explanation:
curved area of hemisphere = 2πr^2
so CSA= 2×22÷7 ×49
308
the cost of polishing the inner surface of hemisphere is 308/100 (10)=30.8 rupees
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