A hemispherical bowl made up of steel have thickness 0.5 cm .The inside radius of bowl is 4 cm . find the volume of steel used in making the bowl
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answer in the picture......
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AbniRaj:
but
answer is wrong
plz help brother
answer is 56.83
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The volume of steel is 56.83 cm³. (Approx value.)
Given data :
Thickness = 0.5 cm
Inner radius = 4 cm
So,
The volume of the inner hollow space is = {(2/3)π(4)³} = {(2/3)×(22/7)× 64} = 134.09 cm³
The radius with included metal is = (4+0.5) = 4.5 cm
The volume with included metal = {(2/3)π(4.5)³}= {(2/3)×(22/7)×(91.125)} = 190.92 cm³
So,the volume of the metal = (190.92-134.09) cm³ = 56.83 cm³ (approx.) (Answer)
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