Question

. A hemispherical bowl of internal and external diameters 6 cm and 10cm is melted

and formed into a right circular cylinder of radius 14 cm. Find the height of the

cylinder.



(Ans: 1

3

cm)​

Answer 1

Answer:

height of the cylinder =  $\frac{1}{3} cm$

Step-by-step explanation:

Internal diameter of the hemispherical bowl is 6 cm

∴ Internal hollow volume = $\frac{4}{3x2}$ x π x $(\frac{6}{2} )^{3}$

And the External volume = $\frac{4}{3x2}$ x π x $(\frac{10}{2} )^{3}$

∴ the material volume = $\frac{4}{3x2}$ x π x $[5^3 - 3^3]$ = $\frac{196}{3}$ x π

If the height of the Right circular cylinder is h cm, then:

π x $14^{2}$ x h = $\frac{196}{3}$ x π

∴ h = $\frac{196}{3x14x14}$ = $\frac{1}{3} cm$