A hemispherical bowl of internal diameter 36 cm contains liquid. This liquid is filled into 72 cylindrical bottles of diameter 6 cm. Find the height of the each bottle, if 10% liquid is wasted in this transfer.
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volume of hemisphere =2/3πr³ = volume of liquid present in bowl
=2/3 × 22/7 × (18)³
=2/3 × 22/7 × 18 × 18 × 18 cm³
now, according to question 10% liquid is wasted by transfer .
so, rest volume of liquid =90℅ of volume of liquid present in bowl
again ,
90℅ of volume of liquid present in bowl = 72 x volume of each bottle
9/10 × 2/3 × 22/7 × 18 × 18 × 18 = 72 × 22/7 × 3 × 3 × H
H = 5.4 cm
=2/3 × 22/7 × (18)³
=2/3 × 22/7 × 18 × 18 × 18 cm³
now, according to question 10% liquid is wasted by transfer .
so, rest volume of liquid =90℅ of volume of liquid present in bowl
again ,
90℅ of volume of liquid present in bowl = 72 x volume of each bottle
9/10 × 2/3 × 22/7 × 18 × 18 × 18 = 72 × 22/7 × 3 × 3 × H
H = 5.4 cm
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